Evaluate ∫ sin^3 x dx/((cos^4 x 3 cos^2 x 1) tan^–1 (sec x cos x)) asked in Integrals calculus by Abhilasha01 ( 376k points) indefinite integral First, get everything in terms of sec(x) tex\int sec^5(x)tan^2(x)dx = \int sec^7(x) sec^5(x)dx = \int sec^7(x)dx \int sec^5(x)dx /tex Use integration by parts on both integrals on the right For the first u = sec 5 (x) and dv = sec 2 (x) dx For the second integral, u = sec 3 (x) and dv = sec 2 (x) dx The answer is =ln(tanxsecx)sinxC "Reminder" intsecxdx=ln(tanxsecx)C Therefore, the integral is int(tan^2xdx)/(secx)= intcosxtan^2xdx =intcosx(sec^2x1)dx =int(secxcosx)dx =ln(tanxsecx)sinxC
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Integral of tan^3(x)sec^2(x)-Integral of tan^2 (x) \square!Find each integral \int \tan ^{2} x \sec ^{2} x d x 🎉 Announcing Numerade's $26M Series A, led by IDG Capital!




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Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!Evaluate the following integral ∫ x 3 tan − 1 x d x Hard View solution > Evaluate the given integral ∫ x sec 2 x d x Hint consider whole $\sec^2 (x)\tan (x)=v $ as its integral then apply by parts to get $x^2\tan^2 (x)(\int 4x\tan^2 (x)) $ again consider $\tan^2 (x) $ as v and apply by parts Note use $\tan^2 (x)=\sec^2 (x)1$ and proceed with the integration join both these parts to get the integral
Integral Of Sec 2 X Sec X Tan X 9 2 Dx For Some Arbitrary Constant C ∫{sec 2 x / (sec x tan x) 9/2 } dx = (for some arbitrary constant c) 1) \(\frac{1}{(\sec x\tan x)^{11 / 2}}\left\{\frac{1}{11}\frac{1}{7}(\sec x\tan x)^{2Evaluate the integral {eq}\int \tan^3(x) \sec^2(x) \, \mathrm{d}x {/eq} Indefinite Integral in Calculus Integration techniques can be used to find antiderivatives of a trigonometric functionX d x = d u Rewriting the given integral expression using the substitution, we have ∫ sec2x dx √25−tan2x = ∫ du √25−u2 = ∫ 1 √52−u2 du ∫ sec 2 x d x 25 − tan 2
E de 3 C) •dx = 1c d) Vati xt c Is sec? Let tan2(x) = sec2(x) − 1 which comes from the Pythagorean identity I = ∫(sec2(x) − 1)sec(x)dx = ∫sec3(x)dx − ∫sec(x)dx The integral of sec(x) is well known I = ∫sec3(x)dx −ln(sec(x) tan(x)) The integral of sec3(x) can be found through integration by parts with u = sec(x) and dv = sec2(x)dx at this link∫sec x/(sec xtan x) dx = ∫sec x/(1/cos x sin x/cos x) dx = ∫sec x cos x/( 1sin x) dx = ∫ 1/(1sin x) dx = ∫(1 sin x)/(1sin x)(1sin x) dx = ∫(1sin




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And if it contains x2 − 1, try x = secu Sometimes you will need to try something a bit different to handle constants other than one EXAMPLE1022 Evaluate Z p 4− 9x2 dx WeCos x dx=dt mathI=\int \tan^2x \sec^3 x dx=\int \frac{\sin^2 x}{ \cos^5 x }dx=\int \frac{t^2} {(1t^2)^3} dt/math Now let us use partial fractionsIf it contains 1x2 try x = tanu;



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1) tan x – sec x C 2) log (1 sec x) C 3) secx tan x C 4) log sin x log cos x C Solution (1) tan x – sec x C ∫(sec x) / (sec x tan x) dx(5x – 1) dx = 5 1) dx = tan (5x 1) 0 x e) x sin x dx = x cos x sin x C Leave blank\\int \tan^{2}x\sec{x} \, dx\ > <




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You can move the $ 2\int \sec^2x \tan^2x dx$ to the left hand side of the equation by addition $$\int \sec^2x \tan^2x dx 2\int \sec^2x \tan^2x dx= tan^2x c, c\in\mathbb{R}$$ Note that once we have a side without an integral on it you need to include a constant of integrationMath\int (secxtanx)^2 dx =\int \frac{dx}{(secxtanx)^2}/math because mathsecxtanx = \frac{1}{secxtanx}/math math\int \frac{dx}{sec^2xtan The given integral I = ∫ tan 3 2x sec 2x dx = ∫ tan 2 2x sec 2x tan 2xdx = ∫ (sec 2 2x 1)sec2x tan 2xdx Let sec 2x = u 2sec2x tan2xdx = du
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Which formula of indefinite integral is not true?The integral intsec^2 x/ (secx tanx )^9/2 dx equals (for some arbitrary constant k ) mathsInstead, write the integrand as $\sec x \tan x \tan^2 x \, (\color{maroon}{\sec x})^{1/2}$ and let $u=\color{maroon}{\sec x}$ Write $\tan^2 x$ in terms of $\color{maroon}{\sec x}$ and note $du$ then is $\sec x\tan x\, dx$



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Let mathT = \displaystyle \int \frac{\sec^3{x}}{\tan^2{x}} \,\mathrm dx/math Recall that math\sin^2{\theta} \cos^2{\theta} \equiv 1\ \therefore \cos^2{\thetaClick here👆to get an answer to your question ️ Evaluate the following integral int√(tan^x) sec^4x dx Join / Login > 12th > Maths > Integrals > Integration by SubstitutionIntegral of tan^2x*sec^4x, trig integral with strategy, integral of tan(x) and sec(x)Steve Chow @ Los Angeles Pierce Collegeblackpenredpenwwwblackpenredpencom




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